Question

There are four men and six women on the city councils. If one council member is selected for a committee at random, how likely is that it is a women?

 

Answer 1

Out of four men and six women, one person can be chosen in ¹⁰C₁ = 10 ways.
Number of ways of selecting one women out of six women = ⁶C₁ = 6 ways.

\[\therefore \text{ Required probability }  = \frac{6}{10} = \frac{3}{5}\]