मराठी

The vector equation of the line x-53=y+47=z-62 is ______.

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प्रश्न

The vector equation of the line `(x - 5)/3 = (y + 4)/7 = (z - 6)/2` is ______.

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उत्तर

The vector equation of the line `(x - 5)/3 = (y + 4)/7 = (z - 6)/2` is `vec"r" = (5hat"i" - 4hat"j" + 6hat"k") + lambda(3hat"i" + 7hat"j" + 2hat"k")`.

Explanation:

The given equation is `(x - 5)/3 = (y + 4)/7 = (z - 6)/2`

Here `vec"a" = (5hat"i" - 4hat"j" + 6hat"k")` and `vec"b" = (3hat"i" + 7hat"j" + 2hat"k")`

Equation of the line is `vec"r" = vec"a" + vec"b"lambda`

Hence, the vector equation of the given line is `vec"r" = (5hat"i" - 4hat"j" + 6hat"k") + lambda(3hat"i" + 7hat"j" + 2hat"k")`

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पाठ 11: Three Dimensional Geometry - Exercise [पृष्ठ २३९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 11 Three Dimensional Geometry
Exercise | Q 39 | पृष्ठ २३९
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