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प्रश्न
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find its perimeter.
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उत्तर
Adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2
∴ Perimeter = 2(2x2 – 5xy + 3z2 + 4xy – x2 – z2)
= 4x2 – 10xy + 6z2 + 8xy – 2x2 – 2z2
= 2x2 – 2xy + 4z2
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संबंधित प्रश्न
Evaluate :
−7x2 + 18x2 + 3x2 − 5x2
Add : 5a + 3b, a − 2b, 3a + 5b
Add : 3b − 7c + 10, 5c − 2b − 15, 15 + 12c + b
Subtract : 6a + 3 from a3 − 3a2 + 4a + 1
Subtract : a2 + ab + b2 from 4a2 − 3ab + 2b2
Take away – 3x3 + 4x2 – 5x+ 6 from 3x3 – 4x2 + 5x – 6
Take m2 + m + 4 from −m2 + 3m + 6 and the result from m2 + m + 1.
Subtract the sum of 5y2 + y – 3 and y2 – 3y + 7 from 6y2 + y – 2.
How much more than 2x2 + 4xy + 2y2 is 5x2 + 10xy – y2 ?
The sides of a triangle are x2 – 3xy + 8, 4x2 + 5xy – 3 and 6 – 3x2 + 4xy. Find its perimeter.
