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प्रश्न
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find its perimeter.
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उत्तर
Adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2
∴ Perimeter = 2(2x2 – 5xy + 3z2 + 4xy – x2 – z2)
= 4x2 – 10xy + 6z2 + 8xy – 2x2 – 2z2
= 2x2 – 2xy + 4z2
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संबंधित प्रश्न
Add : 8x − 3y + 7z, −4x + 5y − 4z, −x − y − 2z
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Subtract : 4xy2 from 3xy2
Subtract : x3 − 4x − 1 from 3x3 − x2 + 6
Take m2 + m + 4 from −m2 + 3m + 6 and the result from m2 + m + 1.
How much more than 2x2 + 4xy + 2y2 is 5x2 + 10xy – y2 ?
If x = 6a + 8b + 9c ; y = 2b – 3a – 6c and z = c – b + 3a ; find :
- x + y + z
- x – y + z
- 2x – y – 3z
- 3y – 2z – 5x
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How much bigger is 5x2y2 – 18xy2 – 10x2y than –5x2 + 6x2y – 7xy?
