Advertisements
Advertisements
प्रश्न
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find its perimeter.
Advertisements
उत्तर
Adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2
∴ Perimeter = 2(2x2 – 5xy + 3z2 + 4xy – x2 – z2)
= 4x2 – 10xy + 6z2 + 8xy – 2x2 – 2z2
= 2x2 – 2xy + 4z2
APPEARS IN
संबंधित प्रश्न
Evaluate :
b2y − 9b2y + 2b2y − 5b2y
Evaluate :
7x − 9y + 3 − 3x − 5y + 8
Evaluate :
3x2 + 5xy − 4y2 + x2 − 8xy − 5y2
Add : 8x − 3y + 7z, −4x + 5y − 4z, −x − y − 2z
Add : x3 − x2y + 5xy2 + y3, - x3 − 9xy2 + y3, 3x2y + 9xy2
Subtract : cab − 4cad − cbd from 3abc + 5bcd − cda
Take away – 3x3 + 4x2 – 5x+ 6 from 3x3 – 4x2 + 5x – 6
How much more than 2x2 + 4xy + 2y2 is 5x2 + 10xy – y2 ?
The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12. Find its third side.
What must be subtracted from 19x4 + 2x3 + 30x – 37 to get 8x4 + 22x3 – 7x – 60 ?
