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प्रश्न
The total number of electrons in the human body is typically in the order of 1028. Suppose, due to some reason, you and your friend lost 1% of this number of electrons. Calculate the electrostatic force between you and your friend separated at a distance of lm. Compare this with your weight. Assume the mass of each person is 60kg and use point charge approximation.
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उत्तर
Number of electrons in the human body = 1028
Number of electrons in me and my friend after lost of 1% = 1028 x 1%
`= 10^28 xx 1/100`
n = 1026 electrons
Separation distance d = 1 m
Charge of each person q = 1026 x 1.6 x 10-19
q = 1.6 x 107 C
Electrostatic force, F = `1/(4 pi epsilon_0) = ("q"_1"q"_2)/"r"^2 = (9 xx 10^9 xx 1.6 xx 10^7 xx 1.6 xx 10^7)/1^2`
F = 2.304 x 1024N
Mass of the person, M = 60 kg
Acceleration due to gravity, g = 9.8 ms-2
Weight (W) = mg
= 60 x 9.8
W = 588 N
Electrostatic force is equal to 3.92 x 1021 times of weight of the person.
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