Question

The slope of the tangent to the curve y = x³ – x at the point (2, 6) is ______.

Answer 1

The slope of the tangent to the curve y = x³ – x at the point (2, 6) is 11.

Explanation:

y = x³ – x

Differentiate w.r.t. x

`dy/dx = 3x^2 - 1`

Slope of the tangent to the curve y = x³ – x at point (2, 6) is

`dy/dx}_((2"," 6)) = 3(2)^2 - 1`

= 3(4) – 1

= 12 – 1

= 11