Question

The slant height of a bucket is 45 cm and the radii of its top and bottom are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

पर्याय

• 4953 cm² 

• 4952 cm² 

• 4951 cm² 

• 4950 cm² 

Answer 1

4950 cm² 

Let the radius of the top and bottom of the bucket be R and r and let its slant height be l.
Then, R = 28 cm, r = 7 cm, l  = 45 cm

curved surface area of the bucket = πl (R + r)

`= 22/7 xx 45 xx (28 + 7)  "cm"^2`

= 4950 cm² 

Hence, the curved surface area of the bucket is 4950 cm².