Advertisements
Advertisements
प्रश्न
The sides of a triangle are x2 – 3xy + 8, 4x2 + 5xy – 3 and 6 – 3x2 + 4xy. Find its perimeter.
बेरीज
Advertisements
उत्तर
Required perimeter = Sum of three sides
= x2 − 3xy + 8 + 4x2 + 5xy − 3 + 6 − 3x2 + 4xy
= x2 + 4x2 − 3x2 − 3xy + 5xy + 4xy + 8 − 3 + 6
= 2x2 + 6xy + 11
shaalaa.com
Combining like Terms
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Evaluate :
3x2 + 5xy − 4y2 + x2 − 8xy − 5y2
Add : 5a + 3b, a − 2b, 3a + 5b
Add : 8x − 3y + 7z, −4x + 5y − 4z, −x − y − 2z
Add : a − 3b + 3; 2a + 5 − 3c; 6c − 15 + 6b
Subtract : 4xy2 from 3xy2
Subtract : 6a + 3 from a3 − 3a2 + 4a + 1
Subtract : cab − 4cad − cbd from 3abc + 5bcd − cda
Subtract the sum of 5y2 + y – 3 and y2 – 3y + 7 from 6y2 + y – 2.
If x = 6a + 8b + 9c ; y = 2b – 3a – 6c and z = c – b + 3a ; find :
- x + y + z
- x – y + z
- 2x – y – 3z
- 3y – 2z – 5x
How much smaller is 15x – 18y + 19z than 22x – 20y – 13z + 26 ?
