मराठी

The side BC of ΔABC is produced to a point D. The bisector of ∠A meets side BC in L. If ∠ABC = 30° and ∠ACD = 115°, then ∠ALC = ______.

Advertisements
Advertisements

प्रश्न

The side BC of ΔABC is produced to a point D. The bisector of ∠A meets side BC in L. If ∠ABC = 30° and ∠ACD = 115°, then ∠ALC = ______.

पर्याय

  •  85°

  • \[72\frac{1}{2}^\circ\]
  • 145°

  • none of these

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

The side BC of ΔABC is produced to a point D. The bisector of ∠A meets side BC in L. If ∠ABC = 30° and ∠ACD = 115°, then ∠ALC = `bbunderline(72 1/2)` °

Explanation:

In the given problem, BC of ΔABC is produced to point D. bisectors of ∠A meet side BC at L, ∠ABC = 30° and ∠ACD = 115°

Here, using the property, “exterior angle of a triangle is equal to the sum of the two opposite interior angles”, we get,

In ΔABC

∠ACD = ∠CAB + ∠CBA

115° = ∠CAB + 30°

∠CAB = 115° - 30°

∠CAB = 85°

Now, as AL is the bisector of  ∠A

∠CAL = 1/2 ∠CAB

∠CAL = 1/2 (85°)

`∠CAL = 44 (1^\circ)/2`

Also, ∠ACD is the exterior angle of ΔALC

Thus,

Again, using the property, “exterior angle of a triangle is equal to the sum of the two opposite interior angles”, we get,

In ΔALC

∠ACD = ∠CAL + ∠ALC

`115= 44 (1^\circ)/2+∠ALC`

`∠ALC =115- 44 1^\circ/2`

`∠ALC = 72 (1^\circ)/2`

Thus, `∠ALC = 72 1^\circ/2  `

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Triangle and its Angles - Exercise 11.4 [पृष्ठ २९]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 9
पाठ 11 Triangle and its Angles
Exercise 11.4 | Q 28 | पृष्ठ २९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

AB is a line seg P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B (See Fig. 10.26). Show that the line PQ is perpendicular bisector of AB. 

 


The vertical angle of an isosceles triangle is 100°. Find its base angles. 


Two lines AB and CD intersect at O such that BC is equal and parallel to AD. Prove that the lines AB and CD bisect at O. 


BD and CE are bisectors of ∠B and ∠C of an isosceles ΔABC with AB = AC. Prove that BD = CE. 


ABC is a triangle in which BE and CF are, respectively, the perpendiculars to the sides AC and AB. If BE = CF, prove that ΔABC is isosceles  


Fill the blank in the following so that the following statement is true. 

If altitudes CE and BF of a triangle ABC are equal, then AB = .... 


Is it possible to draw a triangle with sides of length 2 cm, 3 cm and 7 cm? 

 


Which of the following statements are true (T) and which are false (F)? 

Sum of any two sides of a triangle is greater than the third side. 

 


In the given figure, the sides BC, CA and AB of a Δ ABC have been produced to D, E and F respectively. If ∠ACD = 105° and ∠EAF = 45°, find all the angles of the Δ ABC.


Write the sum of the angles of an obtuse triangle.


If the angles of a triangle are in the ratio 2 : 1 : 3, then find the measure of smallest angle.


In the given figure, if BP || CQ and AC = BC, then the measure of x is


In the given figure, if l1 || l2, the value of x is


In ∆ABC, BC = AB and ∠B = 80°. Then ∠A is equal to ______.


Is it possible to construct a triangle with lengths of its sides as 8 cm, 7 cm and 4 cm? Give reason for your answer.


In the following figure, D and E are points on side BC of a ∆ABC such that BD = CE and AD = AE. Show that ∆ABD ≅ ∆ACE.


CDE is an equilateral triangle formed on a side CD of a square ABCD (Figure). Show that ∆ADE ≅ ∆BCE.


Find all the angles of an equilateral triangle.


In a triangle ABC, D is the mid-point of side AC such that BD = `1/2` AC. Show that ∠ABC is a right angle.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×