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प्रश्न
The ratio between the radius of the base and the height of a cylinder is 2 : 3. If its volume is 1617 cm3, the total surface area of the cylinder is
पर्याय
308 cm2
462 cm2
540 cm2
770 cm2
MCQ
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उत्तर
770 cm2
Let the common multiple be x.
Let the radius of the cylinder be 2x cm and its height be 3x cm.
Then, volume of the cylinder `= pi"r"^2"h"`
`= 22/7xx(2x)^2xx3x`
Therefore,
`22/7xx(2x)^2xx3x=1617`
`=> 22/7xx4x^2xx3x = 1617`
`=>22/7xx12x^3=1617`
`=x^3 = (1617xx7/22xx1/12)`
`= x^3 = (7/2xx7/2xx7/2)`
`=x^3 = (7/2)^3`
`=> x= 7/2`
Now, r = 7 cm and `"h" = 21/2 "cm"`
Hence, the total surface area of the cylinder
`=(2pi"rh"+2pi"r"^2)`
`= 2pi"r"(2xx22/7xx7xx35/2)"cm"^2`
= 770 cm2
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