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प्रश्न
The point of contact of the tangent lo the circle x2 + y2 = 5 at the point (1, –2) which touches the circle, x2 + y2 – 8x + 6y + 20 = 0 is ______.
पर्याय
(2, –1)
(3, –1)
(5, –5)
(5, –1)
MCQ
रिकाम्या जागा भरा
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उत्तर
The point of contact of the tangent lo the circle x2 + y2 = 5 at the point (1, –2) which touches the circle, x2 + y2 – 8x + 6y + 20 = 0 is (3, –1).
Explanation:
Equation of the tangent at (1, –2) to the circle x2 + y2 = 5 is x – 2y = 5
Here, only point (3, –1) lies on the tangent.
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