हिंदी

The point of contact of the tangent lo the circle x2 + y2 = 5 at the point (1, –2) which touches the circle, x2 + y2 – 8x + 6y + 20 = 0 is ______.

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प्रश्न

The point of contact of the tangent lo the circle x2 + y2 = 5 at the point (1, –2) which touches the circle, x2 + y2 – 8x + 6y + 20 = 0 is ______.

विकल्प

  • (2, –1)

  • (3, –1)

  • (5, –5)

  • (5, –1)

MCQ
रिक्त स्थान भरें
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उत्तर

The point of contact of the tangent lo the circle x2 + y2 = 5 at the point (1, –2) which touches the circle, x2 + y2 – 8x + 6y + 20 = 0 is (3, –1).

Explanation:

Equation of the tangent at (1, –2) to the circle x2 + y2 = 5 is x – 2y = 5

Here, only point (3, –1) lies on the tangent.

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