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प्रश्न
The point on the curve y2 = x where tangent makes 45° angle with x-axis is ______________ .
पर्याय
(1/2, 1/4)
(1/4, 1/2)
(4, 2)
(1, 1)
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उत्तर
(1/4, 1/2)
Let the required point be (x1, y1).
The tangent makes an angle of 45o with the x-axis.
∴ Slope of the tangent = tan 45o = 1
\[\text { Since, the point lies on the curve } . \]
\[\text { Hence, } {y_1}^2 = x_1 \]
\[\text { Now,} y^2 = x\]
\[ \Rightarrow 2y\frac{dy}{dx} = 1\]
\[ \Rightarrow \frac{dy}{dx} = \frac{1}{2y}\]
\[\text { Slope of the tangent } = \left( \frac{dy}{dx} \right)_\left( x_1 , y_1 \right) =\frac{1}{2 y_1}\]
\[\text { Given }:\]
\[\frac{1}{2 y_1} = 1\]
\[ \Rightarrow 2 y_1 = 1\]
\[ \Rightarrow y_1 = \frac{1}{2}\]
\[\text{ Now,} \]
\[ x_1 = {y_1}^2 = \left( \frac{1}{2} \right)^2 = \frac{1}{4}\]
\[ \therefore \left( x_1 , y_1 \right) = \left( \frac{1}{4}, \frac{1}{2} \right)\]
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