Advertisements
Advertisements
प्रश्न
When radiations of wavelength λ1 and λ2 are incident on certain photosensitive, such that E1 > E2 . Then Planck's constant 'h' is ......................... .
(C = Velocity of light).
पर्याय
`((E_1 - E_2)(lambda_1 - lambda_2))/(C(lambda_1 * lambda_2))`
`((E_1 - E_2)lambda_1C)/((lambda_1 - lambda_2)lambda_2)`
`((E_1 - E_2)lambda_1lambda_2)/(C(lambda_2 - lambda_1))`
`((lambda_1 - lambda_2)C)/((E_1 - E_2)lambda_1 * lambda_2)`
Advertisements
उत्तर
`((E_1 - E_2)lambda_1lambda_2)/(C(lambda_2 - lambda_1))`
APPEARS IN
संबंधित प्रश्न
The energy of photon of wavelength X is_____ .
[h = Planck’s constant, c = speed of light in vacuum]
The momentum of a photon of de Broglie wavelength 5000Å is _______.
[Planck’s constant = 6.63 x10-34 J.s.]
Find the value of energy of electron in eV in the third Bohr orbit of hydrogen atom.
(Rydberg's constant (R) = 1· 097 x 107m - 1,Planck's constant (h) =6·63x10-34 J-s,Velocity of light in air (c) = 3 x 108m/ s.)
Find the wave number of a photon having energy of 2.072 eV
Given : Charge on electron = 1.6 x 10-19 C,
Velocity of light in air = 3 x 108 m/s,
Planck’s constant = 6.63 x 10-34 J-s.
Define (i) stopping potential and (ii) threshold frequency, using Einstein’s equation and drawing necessary plot between relevant quantities.
Radiation of frequency 1015 Hz is incident on two photosensitive surface P and Q. There is no photoemission from surface P. Photoemission occurs from surface Q but photoelectrons have zero kinetic energy. Explain these observations and find the value of work function for surface Q.
The work function for a metal surface is 2.2eV. If the light of wavelength 5000Å is incident on the surface of the metal, find the threshold frequency and incident frequency. Will there be an emission of photoelectrons or not? (c = 3 x 108 m/ s, 1eV = 1.6x10-19 J , h = 6.63 x 10-34 J.s.)
With reference to the photoelectric effect, define threshold wavelength
Write the basic features of photon picture of electromagnetic radiation on which Einstein’s photoelectric equation is based.
Write Einstein’s photoelectric equation.
According to Einstein’s model, the threshold frequency for a metal having work function ϕ0 is given by _________.
Which of the following graphs correctly represents the variation of maximum kinetic energy (Ek) of photoelectrons with the frequency (𝜈) of the incident radiation?
Calculate the maximum kinetic energy of photoelectrons emitted by a metal (work function = 1.5 eV) when it is illuminated with light of wavelength 198 nm.
According to Einstein's photoelectric equation, the plot of the kinetic energy of the emitted photoelectrons from a metal Vs the frequency of the incident radiation gives as straight the whose slope:
Dimensions of ‘resistance’ are same as (where h is Planck's constant and e is charge):
If the frequency of light in a photoelectric experiment is double the stopping potential will
If the energy of photon corresponding to a wavelength of 6000 A° is 3.32 × 10−19 J, the photon energy for a wavelength of 4000 A° will be ______.
Which of the following is/are true for cathode ray
The wavelength of matter is independent of
(i) A ray of light incident on face AB of an equilateral glass prism, shows minimum deviation of 30°. Calculate the speed of light through the prism.
(ii) Find the angle of incidence at face AB so that the emergent ray grazes along the face AC.
- Calculate the frequency of a photon of energy 6.5 × 10−19 J.
- Can this photon cause the emission of an electron from the surface of Cs of work function 2.14 eV? If yes, what will be the maximum kinetic energy of the photoelectron?
How does stopping potential in photoelectric emission vary if the frequency of incident radiation decreases?
The graphs below show the variation of the stopping potential VS with the frequency (ν) of the incident radiations for two different photosensitive materials M1 and M2.
Express work function for M1 and M2 in terms of Planck’s constant(h) and Threshold frequency and charge of the electron (e).
If the values of stopping potential for M1 and M2 are V1 and V2 respectively then show that the slope of the lines equals to `(V_1-V_2)/(V_(01)-V_(02))` for a frequency,
ν > ν02 and also ν > ν01
