Advertisements
Advertisements
प्रश्न
The perimeter of a rhombus is 40 cm. If one diagonal is 16 cm; find:
- It's other diagonal
- area
Advertisements
उत्तर
(i)
Perimeter of rhombus = 40 cm
Perimeter of rhombus = 4 × side
4 × side = 40
side = `40/4 = 10` cm
One diagonal = 16 cm
Diagonals of a rhombus bisect each other at right angles.
OB = `sqrt("AB"^2 - "OA"^2)`
= `sqrt((10)^2 - (8)^2)`
= `sqrt(100 - 64)`
= `sqrt(36)`
= 6 cm
∴ diagonal BD = `6 xx 2 = 12` cm
(ii)
Area of rhombus = `1/2 xx "product of diagonals"`
= `1/2 xx 12 xx 16`
= 96 cm2
∴ (i) 12 cm (ii) 96 cm2
APPEARS IN
संबंधित प्रश्न
If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, what is the area of the quadrilateral?
The diagonals of a rhombus are 18 cm and 24 cm. Find:
(i) its area ;
(ii) length of its sides.
(iii) its perimeter
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 26 m | 468 sq.m |
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 12 mm | 180 sq.mm |
The area of the rhombus when both diagonals measuring 8 cm is
The area of the rhombus is 128 sq.cm and the length of one diagonal is 32 cm. The length of the other diagonal is
The angle between the diagonals of a rhombus is
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus.
What is the area of the rhombus ABCD below if AC = 6 cm and BE = 4 cm?
