Advertisements
Advertisements
प्रश्न
The perimeter of a rhombus is 40 cm. If one diagonal is 16 cm; find:
- It's other diagonal
- area
Advertisements
उत्तर
(i)
Perimeter of rhombus = 40 cm
Perimeter of rhombus = 4 × side
4 × side = 40
side = `40/4 = 10` cm
One diagonal = 16 cm
Diagonals of a rhombus bisect each other at right angles.
OB = `sqrt("AB"^2 - "OA"^2)`
= `sqrt((10)^2 - (8)^2)`
= `sqrt(100 - 64)`
= `sqrt(36)`
= 6 cm
∴ diagonal BD = `6 xx 2 = 12` cm
(ii)
Area of rhombus = `1/2 xx "product of diagonals"`
= `1/2 xx 12 xx 16`
= 96 cm2
∴ (i) 12 cm (ii) 96 cm2
APPEARS IN
संबंधित प्रश्न
Lengths of the diagonals of a rhombus are 16.5 cm and 14.2 cm, find its area.
The diagonals of a rhombus are 18 cm and 24 cm. Find:
(i) its area ;
(ii) length of its sides.
(iii) its perimeter
The length of the diagonals of a rhombus is in ratio 4 : 3. If its area is 384 cm2, find its side.
A sweet is in the shape of rhombus whose diagonals are given as 4 cm and 5 cm. The surface of the sweet should be covered by an aluminum foil. Find the cost of aluminum foil used for 400 such sweets at the rate of ₹ 7 per 100 sq.cm
The area of the rhombus when both diagonals measuring 8 cm is
The height of the rhombus whose area 96 sq.m and side 24 m is
The angle between the diagonals of a rhombus is
Area of a rhombus = `1/2` product of ______.
The area of a rectangular field is 48 m2 and one of its sides is 6 m. How long will a lady take to cross the field diagonally at the rate of 20 m/minute?
