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प्रश्न
The perimeter of a rectangle is 46 m and its length is 15 m. Find its :
(i) breadth
(ii) area
(iii) diagonal.
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उत्तर
(i)
Perimeter of rectangle = 46 m
length, l = 15 m
2 (l+b) = 46
2(15 + b) = 46
15+b = `46/2` = 23
b = 23 – 15
b = 8 m
(ii)
area = `l xx b = 15 xx 8 = 120 "m"^2`
(iii)
diagonal = `sqrt(l^2 + b^2) = sqrt(15^2 + 8^2)`
= `sqrt(225 + 64) = sqrt(289) = 17`m
Hence (i) 8 m (ii) 120 m2 (iii) 17 m
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