Advertisements
Advertisements
प्रश्न
The order and degree of the differential equation 1 + `((d^3y)/dx^3)^3` = λ `(d^2y)/dx^2` is ______.
पर्याय
Order = 3, Degree = 3
Order = 2, Degree = 2
Order = 3, Degree = 1
Order = 2, Degree = 1
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
The order and degree of the differential equation 1 + `((d^3y)/dx^3)^3` = λ `(d^2y)/dx^2` is Order = 3, Degree = 3.
Explanation:
1 + `((d^3y)/dx^3)^3` = λ `(d^2y)/dx^2`
The derivatives present are the third derivative `((d^3y)/dx^3)` and the second derivative `(d^2y)/dx`.
The highest order derivative is 3.
Therefore, Order = 3
The highest-order derivative is `((d^3y)/dx^3)`
The power (exponent) raised on this specific derivative is 3.
Therefore, Degree = 3
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
