Advertisements
Advertisements
प्रश्न
The nature of the roots of the equation, `3x^2 - 4sqrt(3)x + 4 = 0` is ______.
पर्याय
real and equal
irrational and unequal
rational and unequal
imaginary and unequal
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
The nature of the roots of the equation, `3x^2 - 4sqrt(3)x + 4 = 0` is real and equal.
Explanation:
For `3x^2 - 4sqrt(3)x + 4 = 0`,
a = 3, b = `-4sqrt(3)`, c = 4.
Discriminant D = b2 – 4ac
= `(-4sqrt(3))^2 - 4 xx 3 xx 4`
= 16(3) – 48
= 48 – 48
= 0
So, the roots are real and equal.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
