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प्रश्न
If –5 is a root of the quadratic equation 2x2 + px – 15 = 0 and the quadratic equation p(x2 + x) + k = 0 has equal roots, then the value of k is ______.
पर्याय
`7/4`
`5/4`
`3/4`
`1/4`
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उत्तर
If –5 is a root of the quadratic equation 2x2 + px – 15 = 0 and the quadratic equation p(x2 + x) + k = 0 has equal roots, then the value of k is `underlinebb(7/4)`.
Explanation:
1. Solve for p
Since –5 is a root of the equation 2x2 + px – 15 = 0, it must satisfy the equation when substituted for x:
2(–5)2 + p(–5) – 15 = 0
2(25) – 5p – 15 = 0
50 – 5p – 15 = 0
35 – 5p = 0
5p = 35
p = 7
2. Form the second equation
Substitute the value of p = 7 into the second equation p(x2 + x) + k = 0:
7(x2 + x) + k = 0
7x2 + 7x + k = 0
3. Apply the equal roots condition
For a quadratic equation ax2 + bx + c = 0 to have equal roots, its discriminant (D = b2 – 4ac) must be zero.
Here, a = 7, b = 7 and c = k:
D = (7)2 – 4(7)(k) = 0
49 – 28k = 0
28k = 49
`k = 49/28`
`k = 7/4`
