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प्रश्न
The motion of a particle in the x-y plane is described by a set of following equations x = `4 sin(pi/2 - omegat)` m and y = 4 sin(ωt)m. The path of the particle will be ______.
पर्याय
circular
helical
parabolic
elliptical
MCQ
रिकाम्या जागा भरा
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उत्तर
The motion of a particle in the x-y plane is described by a set of following equations x = `4 sin(pi/2 - omegat)` m and y = 4 sin(ωt)m. The path of the particle will be circular.
Explanation:
x = `4 sin(pi/2 - omegat)` = 4cosωt
Y = 4sinωt
So, x2 + y2 = 42, which is the equation of the circle.
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Introduction of Oscillations
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