हिंदी

The motion of a particle in the x-y plane is described by a set of following equations x = 4sin(π2-ωt) m and y = 4 sin(ωt)m. The path of the particle will be ______.

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प्रश्न

The motion of a particle in the x-y plane is described by a set of following equations x = `4 sin(pi/2 - omegat)` m and y = 4 sin(ωt)m. The path of the particle will be ______.

विकल्प

  • circular

  • helical

  • parabolic

  • elliptical

MCQ
रिक्त स्थान भरें
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उत्तर

The motion of a particle in the x-y plane is described by a set of following equations x = `4 sin(pi/2 - omegat)` m and y = 4 sin(ωt)m. The path of the particle will be circular.

Explanation:

x = `4 sin(pi/2 - omegat)` = 4cosωt

Y = 4sinωt

So, x2 + y2 = 42, which is the equation of the circle.

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