Question

The magnetic field at the centre of a current carrying circular loop of radius R, is B₁. The magnetic field at a point on its axis at a distance R from the center of the loop is B₂. Then the ratio (B₁/B₂) is ______.

पर्याय

• `2sqrt 2`

• `1/sqrt 2`

• `sqrt 2`

• 2

Answer 1

The magnetic field at the centre of a current carrying circular loop of radius R, is B₁ The magnetic field at a point on its axis at a distance R from the center of the loop is B₂. Then the ratio (B₁/B₂) is `bbunderline(2sqrt 2)`.

Explanation:

Magnetic field at the centre

`B_1 = (mu_0 i)/(2 R)`

Magnetic field on the axis

`B_2 = (mu_0 i R^2)/(2(R_2 + R^2)^(3//2))`

= `(mu_0 i)/(2 ^(5//2) R)`

∴ `B_1/B_2 = 2^(3//2)`

= `2 sqrt 2`