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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

The Henry’s law constant of a gas is 6.7 × 10–4 mol/(L bar). Its solubility when the partial pressure of the gas at 298 K is 0.65 bar is ______. - Chemistry

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प्रश्न

The Henry’s law constant of a gas is 6.7 × 10–4 mol/(L bar). Its solubility when the partial pressure of the gas at 298 K is 0.65 bar is ______.

पर्याय

  • 4.355 × 10–4 mol/L

  • 4.355 × 10–2 mol/L

  • 2.225 × 10–6 mol/L

  • 2.225 × 10–2 mol/L

MCQ
रिकाम्या जागा भरा
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उत्तर

The Henry’s law constant of a gas is 6.7 × 10–4 mol/(L bar). Its solubility when the partial pressure of the gas at 298 K is 0.65 bar is 4.355 × 10–4 mol/L.

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Solubility
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पाठ 2: Solutions - Multiple choice questions

संबंधित प्रश्‍न

The solubility of a gas in water ______.


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Which among the following is true for the value of Henry's law constant K?


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Assertion: Water is one of the best solvent.

Reason: H-bonding is present in water molecules.


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Henry's law constant for CH3Br(g) is 0.159 mol dm–3 bar–1 at 25°C. What is the solubility of CH3Br(g) in water at the same temperature and partial pressure of 0.164 bar?


What is Henry's law?


Henry’s law constant of oxygen is 1.4 × 10–3 mol lit–1 atm–1 at 298 K. How much of oxygen is dissolved in 100 ml at 298 K when the partial pressure of oxygen is 0.5 atm?


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Dissolving sugar in water


The solubility of N2 gas in water at 25° C and 1 bar is 6.85 × 10−4 mol L−1. Calculate KH (Henry’s law constant).


The solubility of CH3Br(g) in water is 0.0260 mol/dm3 at 0.164 bar partial pressure and at 25°C. Calculate Henry's law constant.


Henry's constant for \[\ce{CH3Br_{(g)}}\] is 0.159 mol dm−3 bar1 25°C. Calculate its solubility in water at 25°C, if its partial pressure is 0.164 bar.


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