Question

The solubility of N₂ gas in water at 25° C and 1 bar is 6.85 × 10⁻⁴ mol L⁻¹. Calculate K_H (Henry’s law constant).

Answer 1

a.K_H = `S/P = (6.85 xx 10^(-4)  "mol dm"^(-3))/(1 "bar")`

= 6.85 × 10⁻⁴ mol L⁻¹ bar⁻¹

b.S = K_HP = 6.85 × 10⁽⁻⁴⁾ mol L⁻¹ bar⁻¹ × 0.75 bar

= 5.138 × 10⁻⁴ mol L⁻¹