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The general solution of the differential equation ydx – xdy = 0; (Given x, y > 0), is of the form (Where 'c' is an arbitrary positive constant of integration) - Mathematics

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प्रश्न

The general solution of the differential equation ydx – xdy = 0; (Given x, y > 0), is of the form

(Where 'c' is an arbitrary positive constant of integration)

पर्याय

  • xy = c

  • x = cy2

  • y = cx

  • y = cx2

MCQ
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उत्तर १

y = cx

Explanation:

ydx – xdy = 0

`\implies (ydx - xdy)/y^2` = 0

`\implies d(x/y)` = 0

`\implies` x = `1/c y`

`\implies` y = cx.

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उत्तर २

y = cx

Explanation:

ydx – xdy = 0

`\implies` ydx = xdy

`\implies dy/y = dx/x`; on integrating `int dy/y = int dx/x`

loge |y| = loge |x| + loge |c|

Since x, y, c > 0, we write loge y = loge x + loge c

`\implies` y = cx.

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