Question

The figure represents the cross section of a swimming pool 10 m broad, 2 m deep at one end, 3 m deep at the other end. Calculate the volume of water it will hold when full, given that its length is 40 m.

Answer 1

The given figure is a trapezium because 2 opposite sides are parallel.

length of the pool = 40m

height of the trapezium = 10m

Area of cross section = Area of trapezium

= `(1)/(2) xx ("sum of parallel sides") xx "height"`

= `(1)/(2) xx (2 + 3) xx 10`

= 25m²

Volume of the pool = Area of cross section x length

= 25 x 40

= 1000m³

∴ The volume of the pool is 1000m³