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The Equation of the Tangent at (2, 3) on the Curve Y2 = Ax3 + B Is Y = 4x − 5. Find the Values Of A And B ? - Mathematics

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प्रश्न

The equation of the tangent at (2, 3) on the curve y2 = ax3 + b is y = 4x − 5. Find the values of a and b ?

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उत्तर

The slope of the given line y = 4x − 5 is 4

\[y^2 = a x^3 + b . . . \left( 1 \right)\]

\[2y \frac{dy}{dx} = 3a x^2 \]

\[ \Rightarrow \frac{dy}{dx} = \frac{3a x^2}{2y}\]

\[\text { Slope of tangent }= \left( \frac{dy}{dx} \right)_\left( 2, 3 \right) =\frac{12a}{6}=2a\]

\[\text { Given that }\]

\[\text { Slope of tangent = slope of given line }\]

\[2a = 4\]

\[ \Rightarrow a = 2\]

\[\text { Substituting this and }x= 2,y= 3 \text{ in (1), we get }\]

\[9 = 16 + b\]

\[ \Rightarrow b = - 7\]

\[\text { Hence, a}= 2 \text { and }b = - 7\]

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पाठ 16: Tangents and Normals - Exercise 16.2 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 16 Tangents and Normals
Exercise 16.2 | Q 8 | पृष्ठ २८

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