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प्रश्न
The equation of normal to the curve y = sin`((pi)/4 x)` at the point (2, 5) is ______.
पर्याय
x = 2
x + y = 5
x + y = 2
y = 5
MCQ
रिकाम्या जागा भरा
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उत्तर
The equation of normal to the curve y = sin`((pi)/4 x)` at the point (2, 5) is x = 2.
Explanation:
Given curve,
Y = sin`((pi)/4 x)`
`"dy"/"dx" = pi/4 cos (pi/4 x)`
`("dy"/"dx")_(x = 2) = pi/4 cos (pi/2) = 0`
Equation of normal of curve at (2, 5) is,
x - 2 = 0
x = 2
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Application of Derivative in Geometry
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