Question

The equation of normal to the curve y = sin`((pi)/4 x)` at the point (2, 5) is ______.

विकल्प

• x = 2

• x + y = 5

• x + y = 2

• y = 5

Answer 1

The equation of normal to the curve y = sin`((pi)/4 x)` at the point (2, 5) is x = 2.

Explanation:

Given curve,

Y = sin`((pi)/4 x)`

`"dy"/"dx" = pi/4 cos (pi/4 x)`

`("dy"/"dx")_(x = 2) = pi/4 cos (pi/2) = 0`

Equation of normal of curve at (2, 5) is,

x - 2 = 0

x = 2