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प्रश्न
The equation of a simple harmonic progressive wave is given by, y = 5cosπ`[200t - x/150]`, where x and y are in cm and ‘t’ is in second. Then the velocity of the wave is ______.
पर्याय
2 m/s
150 m/s
200 m/s
300 m/s
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उत्तर
The equation of a simple harmonic progressive wave is given by, y = 5cosπ`[200t - x/150]`, where x and y are in cm and ‘t’ is in second. Then the velocity of the wave is 300 m/s.
Explanation:
y = 5cos`[200pit - pi/150x]`
y = Acos(ωt - Kx)
A = 5 cm
ω = 200π
2πf = 200π = 100 Hz
K = `pi/150 = (2pi)/lambda`
λ = 300 cm
V = fλ = `100 xx 300 xx 10^-2 = 300` m/s
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संबंधित प्रश्न
Answer in brief:
What are harmonics and overtones?
A pipe closed at one end can produce overtones at frequencies 640 Hz, 896 Hz, and 1152 Hz. Calculate the fundamental frequency.
Find the fundamental, first overtone, and second overtone frequencies of a pipe, open at both the ends, of length 25 cm if the speed of sound in air is 330 m/s.
A string 1m long is fixed at one end. The other end is moved up and down with frequency of 15 Hz. Due to this, a stationary wave with four complete loops gets produced on the string. Find the speed of the progressive wave which produces the stationary wave.
[Hint: Remember that the moving end is an antinode.]
What are harmonics?
What are overtones?
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(Neglect end correction).
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