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प्रश्न
The energy of an electron in the 3rd orbit of hydrogen atom is –E. The energy of an electron in the first orbit will be
पर्याय
–3E
`(-"E")/3`
`(-"E")/9`
–9E
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उत्तर
–9E
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संबंधित प्रश्न
Assertion: The spectrum of He+ is expected to be similar to that of hydrogen.
Reason: He+ is also one electron system.
The maximum number of electrons in a sub shell is given by the expression
Consider the following electronic arrangements for the d5 configuration.
| ⥮ | ⥮ | 1 | ||
| (a) | ||||
| 1 | 1 | 1 | ⥮ | |
| (b) | ||||
| 1 | 1 | 1 | 1 | 1 |
| (c) | ||||
- which of these represents the ground state.
- which configuration has the maximum exchange energy.
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An atom of an element contains 35 electrons and 45 neutrons. Deduce
- the number of protons
- the electronic configuration for the element
- All the four quantum numbers for the last electron
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\[\ce{He^+_{(g)} -> He^2+_{(g)} + e^-}\]
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| n | l | m | Sub energy level |
| ? | ? | 0 | 4d |
| 3 | 1 | 0 | ? |
| ? | ? | ? | 5p |
| ? | ? | −2 | 3d |
