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प्रश्न
Calculate the energy required for the process.
\[\ce{He^+_{(g)} -> He^2+_{(g)} + e^-}\]
The ionisation energy for the H atom in its ground state is −13.6 ev atom−1.
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उत्तर
\[\ce{He^+_{(g)} -> He^2+_{(g)} + e^-}\]
En = `(-13.6"z"^2)/"n"^2`
E1 = `(-13.6(2)^2)/(1)^2` = −54.4
E∞ = `(-13.6(2)^2)/(∞)^2` = 0
∴ Required Energy for the given process = E∞ – E1 = 0 – (– 54.4) = 54.4 ev
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