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प्रश्न
The distance of the origin (0, 0, 0) from the plane –2x + 6y – 3z = –7 is ______.
पर्याय
1 unit
`sqrt(2)` units
`2sqrt(2)` units
3 units
MCQ
रिकाम्या जागा भरा
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उत्तर
The distance of the origin (0, 0, 0) from the plane –2x + 6y – 3z = –7 is 1 unit.
Explanation:
Distance = `|(-2 xx 0 + 6 xx 0 - 3 xx 0 + 7)/sqrt(4 + 36 + 9)|`
= `7/7`
= 1 unit
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