рдорд░рд╛рдареА

The Difference of Two Numbers is 4. If the Difference of Their Reciprocals is 4/21. Find the Numbers.

Advertisements
Advertisements

рдкреНрд░рд╢реНрди

The difference of two numbers is 4. If the difference of their reciprocals is 4/21. Find the numbers.

Advertisements

рдЙрддреНрддрд░

Let the two numbers be x and x - 4

Given that the difference of two numbers is 4.

By the given hypothesis, we have

`1/(x-4)-1/x=4/21`

`rArr(x-x+4)/(x(x-4))=4/21`

⇒ 84 = 4x(x – 4)

⇒ ЁЭСе2 - 4ЁЭСе - 21 = 0

⇒ ЁЭСе2 - 7ЁЭСе + 3ЁЭСе - 21 = 0

⇒ ЁЭСе(ЁЭСе - 7) + 3(ЁЭСе - 7) = 0

⇒ (ЁЭСе - 7)(ЁЭСе + 3) = 0

⇒ ЁЭСе = 7 ЁЭСЬЁЭСЯ ЁЭСе = -3 and

If x = -3, x – 4 = -3 - 4 = -7

Hence, required numbers are 3, 7 and -3, -7

shaalaa.com
  рдпрд╛ рдкреНрд░рд╢реНрдирд╛рдд рдХрд┐рдВрд╡рд╛ рдЙрддреНрддрд░рд╛рдд рдХрд╛рд╣реА рддреНрд░реБрдЯреА рдЖрд╣реЗ рдХрд╛?
рдкрд╛рда 4: Quadratic Equations - Exercise 4.7 [рдкреГрд╖реНрда релреи]

APPEARS IN

рдЖрд░.рдбреА. рд╢рд░реНрдорд╛ Mathematics [English] Class 10
рдкрд╛рда 4 Quadratic Equations
Exercise 4.7 | Q 16 | рдкреГрд╖реНрда релреи

рд╡реНрд╣рд┐рдбрд┐рдУ рдЯреНрдпреВрдЯреЛрд░рд┐рдпрд▓VIEW ALL [5]

рд╕рдВрдмрдВрдзрд┐рдд рдкреНрд░рд╢реНтАНрди

Solve the following quadratic equation by Factorisation method: x2 + 7x + 10 = 0


Solve for x :

`2/(x+1)+3/(2(x-2))=23/(5x), x!=0,-1,2`


In a class test, the sum of Shefali’s marks in Mathematics and English is 30. Had she got 2 marks more in Mathematics and 3 marks less in English, the product of their marks would have been 210. Find her marks in the two subjects


Solve the following quadratic equations by factorization:

`2/2^2-5/x+2=0`


Two squares have sides x cm and (x + 4) cm. The sum of this areas is 656 cm2. Find the sides of the squares. 


The time taken by a person to cover 150 km was 2.5 hrs more than the time taken in the return journey. If he returned at a speed of 10 km/hr more than the speed of going, what was the speed per hour in each direction?


A girls is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.


The hypotenuse of a right triangle is 25 cm. The difference between the lengths of the other two sides of the triangle is 5 cm. Find the lengths of these sides.


Find the tow consecutive positive odd integer whose product s 483. 


Solve the following quadratic equation by factorisation.

x2 + x – 20 = 0


Solve the following equation: 4x2 + 16x = 0


Solve the following equation:  4x2 - 13x - 12 = 0


Solve the following equation : x2 + 2ab = (2a + b)x


The length of the sides forming a right angle in a triangle are 5x cm and (3x-1) cm. If the area of the triangle is 60cm2, find the hypotenuse.


The area of right-angled triangle is 600cm2. If the base of the triangle exceeds the altitude by 10cm, find the dimensions of the triangle.


Solve the following equation by factorization

x (2x + 1) = 6


Solve the following equation by factorization

3(y2 – 6) = y(y + 7) – 3


A piece of cloth costs Rs. 300. If the piece was 5 metres longer and each metre of cloth costs Rs. 2 less, the cost of the piece would have remained unchanged. How long is the original piece of cloth and what is the rate per metre?


Solve the quadratic equation: x2 – 2ax + (a2 – b2) = 0 for x.


If α and β are roots of the quadratic equation x2 – 7x + 10 = 0, find the quadratic equation whose roots are α2 and β2.


Share
Notifications

Englishрд╣рд┐рдВрджреАрдорд░рд╛рдареА


      Forgot password?
Use app×