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प्रश्न
The diagram alongside shows a force F = 5 N acting at point A produces a moment of force of 6 Nm about point O. What is the diameter of the wheel?
संख्यात्मक
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उत्तर
Force (F) = 5 N
Moment of force about O = 6 Nm
Moment of force = F × ⊥ distance
∴ ⊥ distance (radius of wheel) = \[\dfrac{\text{Moment of force}}{\text{F}}\]
= \[\dfrac{6\ \text{Nm}}{5\ \text{N}}\]
= 1.2 m
∴ Diameter of wheel = 2 × radius
= 2 × 1.2 m
= 2.4 m
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