Advertisements
Advertisements
प्रश्न
The cost of a machine is supposed to depreciate each year at 12% of its value at the beginning of the year. If the machine is valued at Rs. 44,000 at the beginning of 2008, find its value :
(i) at the end of 2009.
(ii) at the beginning of 2007.
Advertisements
उत्तर
Cost of machine in 2008 = Rs. 44,000
Depreciation rate = 12%
(i) ∴ Cost of machine at the end of 2009
= `"P"( 1 - r/100)^n`
= `44,000( 1 - 12/100 )^2`
= `44,000 xx ( 88/100 )^2`
= Rs. 34,073.60
(ii) Cost of machine at the beginning of 2007(P)
A = `"P"( 1 - r/100)^n`
⇒ 44,000 = P`( 1 - 12/100 )^1`
⇒ 44,000 = P`( 88/100 )^1`
⇒ P = `[44,000 xx 100]/88` = Rs. 50,000
APPEARS IN
संबंधित प्रश्न
A sum of money, invested at compound interest, amounts to Rs. 16,500 in 1 year and to Rs. 19,965 in 3 years. Find the rate per cent and the original sum of money invested.
The difference between C.I. and S.I. on Rs. 7,500 for two years is Rs. 12 at the same rate of interest per annum. Find the rate of interest.,
The ages of Pramod and Rohit are 16 years and 18 years respectively. In what ratio must they invest money at 5% p.a. compounded yearly so that both get the same sum on attaining the age of 25 years?
Find the amount and the compound interest payable annually on:
Rs.16000 for 2 years at 15% and 12% for the successive years.
Samidha borrowed Rs.7500 from Shreya at 30% per annum compounded interest. After 2 years, Samidha gave Rs.10000 and a juicer to Shreya to clear the debt. Find the cost of the juicer.
Find the amount and the compound interest on the following:
Rs.8000 for 3years at 10% per annum compounded annually.
Find the amount and the compound interest on the following :
Rs.12000 for 1`(1)/(2)` years at 5% per annum compounded annually.
Find the amount on Rs 36000 in 2 years 15% p.a. compounded annually.
Calculate the rate percent when Rs 28000 amount to Rs 30870 in 2 years at compounded annually.
In how many years will Rs 2000 amount to Rs 2662 at 10% p.a. compound interest?
