Advertisements
Advertisements
प्रश्न
In how many years will Rs 2000 amount to Rs 2662 at 10% p.a. compound interest?
Advertisements
उत्तर
Here P = Rs.2000, A = Rs.2662, r = 10%
Now, `"P"(1 + "r"/100)^"t"` = A
⇒ `2000(1 + 10/100)^"t"`
= 2662
⇒ `(11/10)^"t"`
= `(2662)/(2000)`
= `(1331)/(1000)`
= `(11/10)^3`
By comparing powers, t = 3
Hence time is 3 years.
APPEARS IN
संबंधित प्रश्न
According to a census taken towards the end of the year 2009, the population of a rural town was found to be 64,000. The census authority also found that the population of this particular town had a growth of 5% per annum. In how many years after 2009 did the population of this town reach 74,088 ?
The population of a town decreased by 12% during 1998 and then increased by 8% during 1999. Find the population of the town, at the beginning of 1998, if at the end of 1999 its population was 2,85,120.
A sum of money, invested at compound interest, amounts to Rs. 16,500 in 1 year and to Rs. 19,965 in 3 years. Find the rate per cent and the original sum of money invested.
The difference between C.I. and S.I. on Rs. 7,500 for two years is Rs. 12 at the same rate of interest per annum. Find the rate of interest.,
Mr. Sharma borrowed a certain sum of money at 10% per annum compounded annually. If by paying Rs.19,360 at the end of the second year and Rs. 31,944 at the end of the third year he clears the debt; find the sum borrowed by him.
Samidha borrowed Rs.7500 from Shreya at 30% per annum compounded interest. After 2 years, Samidha gave Rs.10000 and a juicer to Shreya to clear the debt. Find the cost of the juicer.
Find the amount and the compound interest on the following:
Rs.8000 for 3years at 10% per annum compounded annually.
Find the amount and the compound interest on the following :
Rs.12000 for 1`(1)/(2)` years at 5% per annum compounded annually.
Find the amount and compounded interest on Rs.15000 in 2`(1)/(2)` years at 10% p.a. compounded annually.
Calculate the rate percent when Rs 28000 amount to Rs 30870 in 2 years at compounded annually.
