मराठी

The area enclosed by the ellipse abx2a2+y2b2 = 1 is equal to ______. - Mathematics

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प्रश्न

The area enclosed by the ellipse `x^2/"a"^2 + y^2/"b"^2` = 1 is equal to ______.

पर्याय

  • π2ab

  • πab

  • πa2b

  • πab2

MCQ
रिकाम्या जागा भरा
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उत्तर

The area enclosed by the ellipse `x^2/"a"^2 + y^2/"b"^2` = 1 is equal to πab.

Explanation:

Since Area = `4 int_0^"a"  "b"/"a" sqrt("a"^2 - x^2)  "d"x`

= `(4"b")/"a"[x/2 sqrt("a"^2 - x^2) + "a"^2/2 + "a"^2/2 sin^-1  x/"a"]_0^"a"`

= πab.

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पाठ 8: Application Of Integrals - Solved Examples [पृष्ठ १७५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 8 Application Of Integrals
Solved Examples | Q 11 | पृष्ठ १७५

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