मराठी

The age of the father is twice the sum of the ages of his two children. After 20 years, his age will be equal to the sum of the ages of his children. Find the age of the father.

Advertisements
Advertisements

प्रश्न

The age of the father is twice the sum of the ages of his two children. After 20 years, his age will be equal to the sum of the ages of his children. Find the age of the father.

बेरीज
Advertisements

उत्तर

Let the present age (in year) of father and his two children be x, y and z years, respectively.

Now by given condition,

x = 2(y + z)   ......(i)

And after 20 years,

(x + 20) = (y + 20) + (z + 20)

⇒ y + z + 40 = x + 20

⇒ y + z = x – 20

On putting the value of (y + z) in equation (i), we get the present age of father

x = 2(x – 20)

∴ x = 2x – 40

⇒ x = 40

Hence, the father’s age is 40 years.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Pair of Liner Equation in Two Variable - Exercise 3.3 [पृष्ठ २८]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 10
पाठ 3 Pair of Liner Equation in Two Variable
Exercise 3.3 | Q 17 | पृष्ठ २८
आर.डी. शर्मा Mathematics [English] Class 10
पाठ 3 Pair of Linear Equations in Two Variables
EXERCISE 3.9 | Q 9. | पृष्ठ ३.६०

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Solve the following system of equations: 15x + 4y = 61; 4x + 15y = 72


Solve the following system of equations by using the method of elimination by equating the co-efficients.

`\frac { x }{ y } + \frac { 2y }{ 5 } + 2 = 10; \frac { 2x }{ 7 } – \frac { 5 }{ 2 } + 1 = 9`


Solve the following system of linear equations :

2(ax – by) + (a + 4b) = 0

2(bx + ay) + (b – 4a) = 0


Solve (a – b) x + (a + b) y = `a^2 – 2ab – b^2 (a + b) (x + y) = a^2 + b^2`


Solve the following pair of linear equation by the elimination method and the substitution method.

3x – 5y – 4 = 0 and 9x = 2y + 7


Solve the following pair of linear equation by the elimination method and the substitution method.

`x/2 + (2y)/3 = -1 and x - y /3 = 3`


Form the pair of linear equation in the following problem, and find its solutions (if they exist) by the elimination method:

Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu?


Form the pair of linear equation in the following problem, and find its solution (if they exist) by the elimination method:

Meena went to a bank to withdraw ₹ 2000. She asked the cashier to give her ₹ 50 and ₹ 100 notes only. Meena got 25 notes in all. Find how many notes of ₹ 50 and ₹ 100 she received.


Form the pair of linear equation in the following problem, and find its solution (if they exist) by the elimination method:

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, while Susy paid Rs 21 for the book she kept for five days. Find the fixed charge and the charge for each extra day.


If the length of a rectangle is reduced by 5 units and its breadth is increased by 3 units, then the area of the rectangle is reduced by 9 square units. If length is reduced by 3 units and breadth is increased by 2 units, then the area of rectangle will increase by 67 square units. Then find the length and breadth of the rectangle.


By equating coefficients of variables, solve the following equations.

3x - 4y = 7; 5x + 2y = 3


The difference between an angle and its complement is 10° find measure of the larger angle.


If 52x + 65y = 183 and 65x + 52y = 168, then find x + y = ?


Complete the activity.


The sum of the two-digit number and the number obtained by interchanging the digits is 132. The digit in the ten’s place is 2 more than the digit in the unit’s place. Complete the activity to find the original number.

Activity: Let the digit in the unit’s place be y and the digit in the ten’s place be x.

∴ The number = 10x + y

∴ The number obtained by interchanging the digits = `square`

∴ The sum of the number and the number obtained by interchanging the digits = 132

∴ 10x + y + 10y + x = `square`

∴ x + y = `square`   ...(i)

By second condition,

Digit in the ten’s place = digit in the unit’s place + 2

∴ x – y = 2   ...(ii)

Solving equations (i) and (ii)

∴ x = `square`, y = `square`

Ans: The original number = `square`


Difference between two numbers is 3. The sum of three times the bigger number and two times the smaller number is 19. Then find the numbers.


The angles of a triangle are x, y and 40°. The difference between the two angles x and y is 30°. Find x and y.


Evaluate: (1004)3


The ratio of two numbers is 2:3. If 5 is added in each numbers, then the ratio becomes 5:7 find the numbers.

The ratio of two numbers is 2:3.

So, let the first number be 2x and the second number be `square`.

From the given condition,

`((2x) + square)/(square + square) = square/square`

`square (2x + square) = square (square + square)`

`square + square = square + square`

`square - square = square - square`

`- square = - square`

x = `square`

So, The first number = `2 xx square = square`

and, Second number =  `3 xx square = square`

Hence, the two numbers are `square` and `square`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×