Question

The 7^th term of the given Arithmetic Progression (A.P.):

`1/a, (1/a + 1), (1/a + 2)`... is:

पर्याय

• `(1/a + 6)`

• `(1/a + 7)`

• `(1/a + 8)`

• `(1/a + 7^7)`

Answer 1

`bb((1/a + 6))`

Explanation:

Given A.P. is `1/a, (1/a + 1), (1/a + 2)`

Here, first term, A = `1/a`

Common difference D = `1/a + 1 - 1/a` = 1

Then, 7^th term of A.P. = A + (n – 1)D

= `1/a + (7 - 1) xx 1`

= `1/a + 6`