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प्रश्न
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Tharunya was thrilled to know that the football tournament is fixed with a monthly timeframe from 20th July to 20th August 2023 and for the first time in the FIFA Women’s World Cup’s history, two nations host in 10 venues. Her father felt that the game can be better understood if the position of players is represented as points on a coordinate plane. |
- At an instance, the midfielders and forward formed a parallelogram. Find the position of the central midfielder (D) if the position of other players who formed the parallelogram are :- A(1, 2), B(4, 3) and C(6, 6)
- Check if the Goal keeper G(–3, 5), Sweeper H(3, 1) and Wing-back K(0, 3) fall on a same straight line.
[or]
Check if the Full-back J(5, –3) and centre-back I(–4, 6) are equidistant from forward C(0, 1) and if C is the mid-point of IJ. - If Defensive midfielder A(1, 4), Attacking midfielder B(2, –3) and Striker E(a, b) lie on the same straight line and B is equidistant from A and E, find the position of E.
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उत्तर
i. Let D be (a, b), then
Mid point of AC = Midpoint of BD
`((1 + 6)/2, (2 + 6)/2) = ((4 + a)/2, (3 + b)/2)`
4 + a = 7
a = 3
3 + b = 8
b = 5
Central midfielder is at (3, 5)
ii. GH = `sqrt((-3 - 3)^2 + (5 - 1)^2`
= `sqrt(36 + 16)`
= `sqrt(52)`
= `2sqrt(13)`
GK = `sqrt((0 + 3)^2 + (3 - 5)^2`
= `sqrt(9 + 4)`
= `sqrt(13)`
HK = `sqrt((3 - 0)^2 + (1 - 3)^2`
= `sqrt(9 + 4)`
= `sqrt(13)`
GK + HK = GH `\implies` G,H and K lie on a same straight line
[or]
CJ = `sqrt((0 - 5)^2 + (1 + 3)^2`
= `sqrt(25 + 16)`
= `sqrt(41)`
CI = `sqrt((0 + 4)^2 + (1 - 6)^2`
= `sqrt(16 + 25)`
= `sqrt(41)`
Full-back J(5, –3) and centre-back I(–4, 6) are equidistant from forward C(0, 1)
Mid-point of IJ = `((5 - 4)/2, (-3 + 6)/2) = (1/2, 3/2)`
C is NOT the mid-point of IJ
iii. A, B and E lie on the same straight line and B is equidistant from A and E
⇒ B is the mid-point of AE
`((1 + a)/2, (4 + b)/2)` = (2, – 3)
1 + a = 4 ; a = 3.
4 + b = -6; b = –10 E is (3, –10)
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संबंधित प्रश्न
If the point P(2, 2) is equidistant from the points A(−2, k) and B(−2k, −3), find k. Also find the length of AP.
Find the distance between the following pairs of points:
(−5, 7), (−1, 3)
Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer:
(- 1, - 2), (1, 0), (- 1, 2), (- 3, 0)
Find the distance of the following points from the origin:
(i) A(5,- 12)
Find the value of a if the distance between the points (5 , a) and (1 , 5) is 5 units .
ABC is an equilateral triangle . If the coordinates of A and B are (1 , 1) and (- 1 , -1) , find the coordinates of C.
Using distance formula decide whether the points (4, 3), (5, 1), and (1, 9) are collinear or not.
The distance between the points (0, 5) and (–5, 0) is ______.
Case Study -2
A hockey field is the playing surface for the game of hockey. Historically, the game was played on natural turf (grass) but nowadays it is predominantly played on an artificial turf.
It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.
Each team plays with 11 players on the field during the game including the goalie. Positions you might play include -
- Forward: As shown by players A, B, C and D.
- Midfielders: As shown by players E, F and G.
- Fullbacks: As shown by players H, I and J.
- Goalie: As shown by player K.
Using the picture of a hockey field below, answer the questions that follow:

What are the coordinates of the position of a player Q such that his distance from K is twice his distance from E and K, Q and E are collinear?
Name the type of triangle formed by the points A(–5, 6), B(–4, –2) and C(7, 5).

