Advertisements
Advertisements
प्रश्न
Suppose you are given a circle. Describe a method by which you can find the center of this circle.
Advertisements
उत्तर

To draw the center of a given circle :
1. Draw the circle.
2. Take any two different chords AB and CD of this circle and draw perpendicular bisector of these chords.
3. let these perpendicular bisectors meet at point O.
So, O will be the center of the given circle.
APPEARS IN
संबंधित प्रश्न
In Fig. 8, O is the centre of a circle of radius 5 cm. T is a point such that OT = 13 cm and OT intersects circle at E. If AB is a tangent to the circle at E, find the length of AB, where TP and TQ are two tangents to the circle.

In Fig. 1, QR is a common tangent to the given circles, touching externally at the point T. The tangent at T meets QR at P. If PT = 3.8 cm, then the length of QR (in cm) is :

(A) 3.8
(B) 7.6
(C) 5.7
(D) 1.9
Fill in the blanks:
The longest chord of a circle is a __________ of the circle.
If the area of a circle is equal to sum of the areas of two circles of diameters 10 cm and 24 cm, then the diameter of the larger circle (in cm) is:
An equilateral triangle ABC is inscribed in a circle with centre O. The measures of ∠BOCis
Number of circles that can be drawn through three non-collinear points is
The center of a circle is at point O and its radius is 8 cm. State the position of a point P (point P may lie inside the circle, on the circumference of the circle, or outside the circle), when:
(a) OP = 10.6 cm
(b) OP = 6.8 cm
(c) OP = 8 cm
In the given figure, point P is 26 cm away from the centre O of a circle and the length PT of the tangent drawn from P to the circle is 24 cm. Then the radius of the circle is ______
Find the length of the arc of a circle which subtends an angle of 60° at the centre of the circle of radius 42 cm.
If an are subtends an angle of 90° at the centre of a circle, then the ratio of its length to the circumference of the circle is ______.
