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प्रश्न
Study the extract of the Periodic Table given below and answer the questions that follow. Give the alphabet corresponding to the element in question. DO NOT repeat an element.
- Which element forms covalent compound with G?

- The ion of which element will migrate towards the cathode during electrolysis?
- Which non-metallic element has the valency 2?
- Which is an inert gas?
- Which element has the lowest electronegativity in the second column?
- Which element is the most metallic?
- State the type of bond formed between I and E. Write its formula.
- Draw the electron dot diagram of the compound formed between I and G.
रासायनिक समीकरणे/रचना
सविस्तर उत्तर
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उत्तर
- G being present in group 17 is a non-metal; covalent bonds form between non-metals. Element A being a non-metal shares its single electron with G to form the stable molecule AG.
- The cathode is the negative electrode, attracting positive ions (cations). Element B is a metal that loses electrons to form a B2+ cation.
- E is a non metal which belongs to group 16. Hence has the valency of 2.
- F is present in group 18 and all group 18 elements are inert gases.
- Electronegativity decreases down a group. In the second column, I is below B, so I has the lowest electronegativity.
- Metallic character increases down a group and decreases from left to right across a period. Since H is towards the bottom left of the given table, it is the most metallic element.
- I is a metal of group 2 and has valency 2. E is a non-metal of group 16 and also has valency 2. Therefore, electrons are transferred from I to E, forming an ionic compound with the formula IE.
\[ \begin{array}{ccccl} & & \begin{array}{c} {\scriptstyle \bullet\,\bullet} \\[-4pt] {\scriptstyle \bullet}\,\mathrm{G}\,\begin{smallmatrix} \bullet \\[-4pt] \bullet \end{smallmatrix} \\[-4pt] {\scriptstyle \bullet\,\bullet} \end{array} & & \\[-4pt] & {\Large \nearrow} & & & \\[-6pt] \mathrm{I}\,\begin{smallmatrix} \bullet \\[-4pt] \bullet \end{smallmatrix} & + & & \quad \longrightarrow \quad & [\,\mathrm{I}\,]^{2+}\;\; 2\left[ \begin{array}{c} {\scriptstyle \bullet\,\bullet} \\[-4pt] \begin{smallmatrix} \bullet \\[-4pt] \bullet \end{smallmatrix}\,\mathrm{G}\,\begin{smallmatrix} \bullet \\[-4pt] \bullet \end{smallmatrix} \\[-4pt] {\scriptstyle \bullet\,\bullet} \end{array} \right]^{-} \\[-6pt] & {\Large \searrow} & & & \\[-4pt] & & \begin{array}{c} {\scriptstyle \bullet\,\bullet} \\[-4pt] {\scriptstyle \bullet}\,\mathrm{G}\,\begin{smallmatrix} \bullet \\[-4pt] \bullet \end{smallmatrix} \\[-4pt] {\scriptstyle \bullet\,\bullet} \end{array} & & \end{array} \]
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