मराठी

State giving reasons, whether the following nuclear mutation is possible or not. (Star indicates an excited state) Z⁢XA ⟶Z−2⁢X1A−4 +2⁢He4

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प्रश्न

State giving reasons, whether the following nuclear mutation is possible or not. (Star indicates an excited state)

\({ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}} \longrightarrow{ }_{\mathrm{Z}-2} \mathrm{X}_{1}{ }^{\mathrm{A}-4}+{ }_{2} \mathrm{He}^{4}\)

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उत्तर

This mutation is possible. It is alpha decay. The nucleus emits an alpha particle \(\left({}_{2}\mathrm{He}^{4}\right)\), so the mass number decreases by 4 and the atomic number decreases by 2. Both the mass number and the atomic number are balanced on both sides, and a new element X1 is formed.

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पाठ 11: Radioactivity - EXERCISE [पृष्ठ २६७]

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 10
पाठ 11 Radioactivity
EXERCISE | Q 12. (b) | पृष्ठ २६७
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