Question

Consider the following standard electrode potential values:

\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\], E⁰ = +0.77 V

\[\ce{MnO^{-4}_{ (aq)} + 8H^+ + 5e^- -> Mn^{2+}_{ (aq)} + 4H2O_{(l)}}\], E⁰ = +1.51 V

What is the cell potential for the redox reaction?

पर्याय

• −2.28 V

• −0.74 V

• +0.74 V

• +2.28 V

Answer 1

+0.74 V

Explanation:

Cell potential (E) = \[\ce{E_{cathode} − E_{anode}}\]

= 1.51 − 0.77

= 0.74 V