Question

Solve `x^2-(sqrt3+1)x+sqrt3=0`

Answer 1

`x^2-(sqrt3+1)x+sqrt3=0` 

⇒ `x^2-sqrt3x-x+sqrt3=0` 

⇒`x(x-sqrt3)-1(x-sqrt3)=0` 

⇒` (x-sqrt3) (x-1)=0` 

⇒`x-sqrt3=0  or  x-1=0` 

⇒` x=sqrt3  or  x=1` 

Hence, `1 and sqrt3` are the roots of the given equation.