Question

Solve` 2x^2+ax-a^2=0`

Answer 1

`2x^2+ax-a^2=0` 

⇒`2x^2+2ax-ax-a^2` 

⇒`2x(x+a)-a(x+a)=0` 

⇒`(x+a)(2x-a)=0` 

⇒`x+a=0  or  2x-a=0` 

⇒`x=-a  or  x=a/2` 

Hence, `a and a/2` are the roots of the given equation.