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प्रश्न
Solve the following simultaneous equation.
2x - y = 5 ; 3x + 2y = 11
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उत्तर
2x - y = 5 ...(I)
3x + 2y = 11 ...(II)
Multiplying (I) with 2 we get
4x - 2y = 10 ...(III)
Adding (II) with (III)
3x + 2y = 11
+ 4x - 2y = 10
7x = 21
⇒ x = 3
Putting the value of x in (I) we get
∴ 2x - y = 5
⇒ 2 × 3 - y = 5
⇒ 6 - y = 5
⇒ y = 1
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So, let the first number be 2x and the second number be `square`.
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