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Solve the following linear programming problems by graphical method. Maximize Z = 22x1 + 18x2 subject to constraints 960x1 + 640x2 ≤ 15360; x1 + x2 ≤ 20 and x1, x2 ≥ 0. - Business Mathematics and Statistics

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प्रश्न

Solve the following linear programming problems by graphical method.

Maximize Z = 22x1 + 18x2 subject to constraints 960x1 + 640x2 ≤ 15360; x1 + x2 ≤ 20 and x1, x2 ≥ 0.

आलेख
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उत्तर

Given that 960x1 + 640x2 ≤ 15360

Let 960x1 + 640x2 = 15360

3x1 + 2x2 = 48

x1 0 16
x2 24 0

Also given that x1 + x2 ≤ 20

Let x1 + x2 = 20

x1 0 20
x2 20 0

To get point of intersection

3x1 + 2x2 = 48 …..(1)

x1 + x2 = 20 ……(2)

− 2x1 – 2x2 = – 40 …..(3) ......[Equation (2) × –2]

x1 = 8 .....[Adding equation (1) and (3)]

x1 = 8 substitute in (2),

8 + x2 = 20

x2 = 12

The feasible region satisfying all the given conditions is OABC.

The co-ordinates of the comer points are O(0, 0), A(16, 0), B(8,12) and C(0, 16).

Corner points Z = 22x1 + 18x2
O(0, 0) 0
A(16, 0) 352
B(8, 12) 392
C(0, 20) 360

The maximum value of Z occurs at B(8, 12).

∴ The optimal solution is x1 = 8, x2 = 12 and Zmax = 392

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पाठ 10: Operations Research - Exercise 10.1 [पृष्ठ २४४]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
पाठ 10 Operations Research
Exercise 10.1 | Q 4. (ii) | पृष्ठ २४४

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