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प्रश्न
Solve the following Linear Programming Problem graphically:
Maximize: P = 70x + 40y
Subject to: 3x + 2y ≤ 9,
3x + y ≤ 9,
x ≥ 0,y ≥ 0.
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उत्तर
Zmax = 70x + 40y
3x + 2y = 9
| x | 3 | 0 |
| y | 0 | 9/2 |
3x + y = 9
| x | 3 | 0 |
| y | 0 | 9 |
ZA = 70 × 3 + 40 × 0 = 210
ZB = `0 + 40 xx 9/2 = 180`
ZC = 0
So, Zmax = 210 at A(3, 0).
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