Advertisements
Advertisements
प्रश्न
Solve the following inequation
6x – 7 ≥ 35, where x is an integer
Advertisements
उत्तर
6x – 7 ≥ 35
Adding 7 on both the sides
6x – 7 + 7 ≥ 35 + 7
6x ≥ 42
Dividing both the sides by 6 we get `(6x)/6` ≥ `42/6`
x ≥ 7
Since the solution belongs to the set of integers that are greater than or equal to 7, we take the values of x as 7, 8, 9, 10 …
APPEARS IN
संबंधित प्रश्न
Solve: `"2x"/3 - ("x" - 1)/6 + ("7x" - 1)/4 = 2 1/6` Hence, find the value of 'a', if `1/"a" + 5"x" = 8`
Solve:
`5x − (4x + (5x - 4)/7) = (4x - 14)/3`
28 is 12 less than 4 times a number. Find the number.
The length of a rectangle is twice its width. If its perimeter is 54 cm; find its length.
A rectangle’s length is 5 cm less than twice its width. If the length is decreased by 5 cm and width is increased by 2 cm; the perimeter of the resulting rectangle will be 74 cm. Find the length and width of the origi¬nal rectangle.
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
Solve:
13(x − 4) - 3(x − 9) − 5(x + 4) = 0
Solve: `("6x" + 1)/2 + 1 = ("7x" - 3)/3`
Given that x ≥ y. Fill in the blank with suitable inequality sign
x + 6 `square` y + 6
Solve the following inequalities
−13 ≤ 5x + 2 ≤ 32, x is an integer
